Name: Ken Gilbert E-Mail: ride5000@ride.ri.net Date: 1/13/100 6:00 PM Subject: Re: simple low pass fiter Ok Ricky, here's a few hints for you. As the order of a filter goes up, the "exact-ness" of it's characteristics goes up as well... ie you get a steeper slope of rolloff. OTOH, the complexity of the circuit goes up, as does it's tendency to resonate at some given frequency. A first order filter does not self-resonate. Anything above that will. I suggest either a first or second order filter. A first order filter is simply--in your case--an inductor in series with the woofer. The equation for the value of inductance is: L = Rl / 6.28 * f where Rl is the load impedance, and f is your desired crossover frequency. In your case, we've got the following equation: L = 4 / 6.28 * 100 = 4 / 628 = .00637 H, or 6.37 mH of inductance. These inductors should be available from MCM Electronics or Parts Express, or any number of mail order places. Again, AIR-CORE inductors are MUCH better than any cored types for high level (speaker) use. Now, for a second order filter, you need to add a cap. There are also different RESPONSES of 2nd order filters, namely Linkwitz-Riley, Bessel, or Chebychev. They all have slightly different phase responses and propensities to ring. The best, in this application (and in most) is the Linkwitz-Riley. The equation for the inductor is: L = 0.3183 * Rl / f Substituting: L = 0.3183 * 4 / 100 = .01273 H, or 12.7 mH. for the cap: C = 0.0796 / Rl * f Substituting: C = 0.0796 / 4 * 100 = .000199 F, or about 200 microfarads. In the second order filter, the cap goes in parallel with the woofer, and the inductor in series between the + lead of the woofer and the + lead of the amp. The cap will need to withstand the peak voltage impressed across the woofer's voice coil, which can be solved with: P = V^2 / R solving for V: V = sqrt (P*R) remember that an amps PEAK power is double the RMS rating. subbing: V = sqrt (800) = 28.3 volts. So you should use a 30V rated cap, at least. Also remember that the cap must be NONPOLAR, since the waveform is completely AC with no DC offset. Hope this helps. ken